A current of 0.15 A is passed through an aqueous solution of K2PtCl4. How long will it take to deposit 1.00 g Pt(s) (M = 195.1)? | Electrochemistry | TheChemSolver

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Question

A current of 0.15 A is passed through an aqueous solution of K₂PtCl₄. How long will it take to deposit 1.00 g Pt(s) (M = 195.1)?

A.

1600 s

B.

3300 s

C.

6600 s

✓ Correct

D.

13000 s

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