Barium chloride reacts with sodium sulfate according to the following equation: BaCl2(aq) + Na2SO4(a — Stoichiometry Chemistry Question
Question
Barium chloride reacts with sodium sulfate according to the following equation:
BaCl2(aq) + Na2SO4(aq) → BaSO4(s) + 2 NaCl(aq)
A student mixes a solution containing 10.0 g BaCl2 (M = 208.2) with a solution containing 10.0 g Na2SO4 (M = 142.1) and obtains 12.0 g BaSO4 (M = 233.2). What is the percent yield of this reaction?
A.
60.0%
B.
73.1%
C.
93.3%
D.✓ Correct
The isolated barium sulfate is most likely wet, since the yield would otherwise be greater than 100%.
💬
Still have doubts about this question?
Practice more questions like this, completely free.