Given the standard enthalpy changes for the reactions: P4(s) + 3 O2(g) → P4O6(s) ΔHº = –1640 kJ mol– — Thermodynamics Chemistry Question
Question
Given the standard enthalpy changes for the reactions:
P4(s) + 3 O2(g) → P4O6(s) ΔHº = –1640 kJ mol–1
P4(s) + 5 O2(g) → P4O10(s) ΔHº = –2940 kJ mol–1
Calculate the standard enthalpy change ∆Hº for the following reaction:
P4O6(s) + 2 O2(g) → P4O10(s)
A.
–4.58 × 10^3 kJ mol–1
B.✓ Correct
–1.30 × 10^3 kJ mol–1
C.
1.79 kJ mol–1
D.
4.82 × 10^6 kJ mol–1
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