The reaction of tert-butyl bromide with azide ion in aqueous solution is proposed to proceed by the — Kinetics Chemistry Question
Question
The reaction of tert-butyl bromide with azide ion in aqueous solution is proposed to proceed by the following mechanism:
(CH3)3CBr(aq) ⇌ (CH3)3C+(aq) + Br–(aq) (rate constants k1 forward, k–1 reverse)
(CH3)3C+(aq) + N3–(aq) → (CH3)3CN3(aq) (rate constant k2)
Assuming that (CH3)3C+(aq) achieves a steady-state concentration, but making no further assumptions about the relative magnitudes of the three rate constants, what is the rate law for this reaction?
A.
Rate = k1[(CH3)3CBr]
B.
Rate = k2[(CH3)3CBr][N3–]
C.
Rate = k1k2[(CH3)3CBr][N3–] / (k–1[Br–])
D.✓ Correct
Rate = k1k2[(CH3)3CBr][N3–] / (k–1[Br–] + k2[N3–])
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